{"id":58,"date":"2008-09-22T21:55:12","date_gmt":"2008-09-22T21:55:12","guid":{"rendered":"http:\/\/wordpress.vipos.rs\/index.php\/2008\/09\/22\/opta-informisanost-i\/"},"modified":"2008-09-22T21:55:12","modified_gmt":"2008-09-22T21:55:12","slug":"opta-informisanost-i","status":"publish","type":"post","link":"https:\/\/va.akademijazs.edu.rs\/index.php\/2008\/09\/22\/opta-informisanost-i\/","title":{"rendered":"Op\u0161ta informisanost I"},"content":{"rendered":"
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<\/strong><\/p>\n<\/td>\n

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1. grupa <\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Zaokru\u017eite ta\u010dan odgovor<\/strong><\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
<\/a><\/td>\n<\/a><\/td>\n<\/tr>\n
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1.<\/p>\n<\/td>\n

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Oblast definisanosti funkcije y = 1\/x je:<\/p>\n

a. R<\/p>\n

b. x \u00b9 0<\/strong><\/p>\n

c. x > 0<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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2.<\/p>\n<\/td>\n

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Domen funkcije y = log(x+1) je skup:<\/p>\n

a. x > 0<\/p>\n

b. R<\/p>\n

c. x > -1<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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3.<\/p>\n<\/td>\n

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Jedna\u010dina \u00bdx-3 \u00bd = -1 ima:<\/p>\n

a. 2 re\u0161enja<\/p>\n

b. 1 re\u0161enje<\/p>\n

c. nema re\u0161enja<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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4.<\/p>\n<\/td>\n

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Re\u0161enje jedna\u010dine log 10x=5 je:<\/p>\n

a. x = 10 5<\/tt><\/code><\/strong><\/p>\n

b. x = 1<\/p>\n

c. x = 5<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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5.<\/p>\n<\/td>\n

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Izraz log xy = logx + logy je ta\u010dan:<\/p>\n

a. za svako x \u0152 R<\/p>\n

b. za x \u2260 \u00b90 i y \u2260 \u00b9 0<\/p>\n

c. za x > 0 i y > 0<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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6.<\/p>\n<\/td>\n

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Vrednost izraza log 525 je:<\/p>\n

a. 2<\/strong><\/p>\n

b. 5<\/p>\n

c. -2<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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7.<\/p>\n<\/td>\n

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Vrednost izraza log 10<\/span>(-10) je:<\/p>\n

a. 1<\/p>\n

b. -1<\/p>\n

c. nije definisana<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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8.<\/p>\n<\/td>\n

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Jedna\u010dina (x + 2) 2 + (y – 1) 2 = 3 je:<\/p>\n

a. krug sa centrom (-2, 1)<\/strong><\/p>\n

b. krug sa centrom (2, -1)<\/p>\n

c. krug sa centrom (3, 3)<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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9.<\/p>\n<\/td>\n

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Jedna\u010dina y = 3 je prava:<\/p>\n

a. paralelna sa y-osom<\/p>\n

b. paralelna sa x-osom<\/strong><\/p>\n

c. nije paralelna ni sa jednom osom<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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10.<\/p>\n<\/td>\n

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Vrednost izraza sin 2x + cos 2x jednaka je:<\/p>\n

a. 1<\/strong><\/p>\n

b. 0<\/p>\n

c. -1<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
\n

11.<\/p>\n<\/td>\n

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Jedna\u010dina prave koja sadr\u017ei ta\u010dke A (0, 3) i B (1, 0) je:<\/p>\n

a. 3x + y – 3 = 0<\/strong><\/p>\n

b. x + y + 3 = 0<\/p>\n

c. x – y + 3 = 0<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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12.<\/p>\n<\/td>\n

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Jedna\u010dina prave koja sadr\u017ei ta\u010dku A (-3, -4) i normalna je na pravu 3x – 5y – 11 = 0<\/p>\n

a. -3x + 5y + 27 = 0<\/p>\n

b. 3x + 5y + 11 = 0<\/p>\n

c. 5x + 3y + 27 = 0<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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13.<\/p>\n<\/td>\n

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Prava 6x + y – 6 = 0 se\u010de parabolu y 2 = 18x :<\/p>\n

a. u 2 ta\u010dke<\/strong><\/p>\n

b. u 1 ta\u010dki<\/p>\n

c. nema preseka<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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14.<\/p>\n<\/td>\n

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Zbir prvih 6 \u010dlanova geometrijske progresije, \u010diji je koli\u010dnik 2, iznosi 63. Sedmi \u010dlan progresije je:<\/p>\n

a. 16<\/p>\n

b. 32<\/p>\n

c. 64<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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15.<\/p>\n<\/td>\n

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Re\u0161enje jedna\u010dine 10 x-4= 0,01 je:<\/p>\n

a. -2<\/p>\n

b. 2<\/strong><\/p>\n

c. 1<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
\n

16.<\/p>\n<\/td>\n

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Sistem jedna\u010dina: x – y = 2 i 3x – 2y = 9 ima re\u0161enje:<\/p>\n

a. x = 5 i y = 3<\/strong><\/p>\n

b. x = 3 i y = 5<\/p>\n

c. nema re\u0161enja<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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17.<\/p>\n<\/td>\n

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Re\u0161enje kvadratne jedna\u010dine x 2 + 6x + 9 su:<\/p>\n

a. x 1 = 3 i x 2 = -3<\/p>\n

b. x 1 = x 2 = -3<\/strong><\/p>\n

c. x 1 = -3 i x 2 = 3<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
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18.<\/p>\n<\/td>\n

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Re\u0161enje sistema jedna\u010dina x 2 + y 2 = 25 i x 2 – y 2 = 7 je: <\/p>\n

a. (4, 3)<\/p>\n

b. (-4, -3)<\/p>\n

c. (4, 3), (-4, -3), (4, -3), (-4, 3)<\/strong><\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
\n

19.<\/p>\n<\/td>\n

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Nakon izvr\u0161enog stepenovanja izraz (4a – 2b) 2 glasi:<\/p>\n

a. 16a 2 + 16ab + 4b 2<\/p>\n

b. 16a 2 – 16ab + 4b 2<\/strong><\/p>\n

c. 16a 2 – 4b 2<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n
\n

20.<\/p>\n<\/td>\n

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Date su prave y = 2x + 1 i y = kx – 3. Da bi prave bile paralelne k \u0107e biti:<\/p>\n

a. k = 2<\/strong><\/p>\n

b. k = 1<\/p>\n

c. k = -2<\/p>\n<\/td>\n<\/tr>\n

 <\/td>\n <\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/blockquote>\n<\/blockquote>\n


<\/p>\n","protected":false},"excerpt":{"rendered":"

1. grupa Zaokru\u017eite ta\u010dan odgovor 1. Oblast definisanosti funkcije y = 1\/x je: a. R b. x \u00b9 0 c. x > 0     2. Domen funkcije y = log(x+1) je skup: a. x > 0 b. R c. x > -1     3. Jedna\u010dina \u00bdx-3 \u00bd = -1 ima: a. 2 re\u0161enja…
Op\u0161irnije…<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[18],"tags":[],"class_list":["post-58","post","type-post","status-publish","format-standard","hentry","category-c23-primeri-testova","wpautop"],"_links":{"self":[{"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/posts\/58","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/comments?post=58"}],"version-history":[{"count":0,"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/posts\/58\/revisions"}],"wp:attachment":[{"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/media?parent=58"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/categories?post=58"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/va.akademijazs.edu.rs\/index.php\/wp-json\/wp\/v2\/tags?post=58"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}